Bar Bending SchedleQC/ QS Engineering

Bar bending schedule Of Circular Column

Bar bending schedule Of Circular Column

B.B.S for Circular RCC Column.

Hello Civil Engineers This article is about How to prepare B.B.S for Column.
To preparing B.B.S for a column. There are some criteria and assumptions that require to be met Let’s get started.

Bar Bending Schedule of Circular Column

Forces on Column.

U should know the normal forces action on a column.

Just look at the diagram that is given below

If you see the shear force and bending moment diagram, the column has less moments at center and more at bottom and top.

When bending moment is maximum not at any time tie a column at top & bottom every rime tie the column at center.

At site tie the bars at the height of 4 to 5 feet. The height of roof should not be more than 11 feet.

  1. Use less cutting of steel and provide desirable lapping.
  2. Lap another steels at same time.
  3. Overlap the top steels with bottom steels.
  4. Between the laps end to end spacing should be provided.

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Bar Bending Schedule For Footing

Bar Bending Schedule (B.B.S) Used by.

B.B.S is used by different kind of peoples and officials on construction site which is given below:

  1. Quantity Surveyor
  2. Steel fixer
  3. Contractor
  4. Project manager
  5. Inspectors
  6. Clerks of construction

In Construction site all Estimation & Costing operation is the responsibilities of the Quantity Surveyor. The v gives the details to quantity surveyor for finding out the number of steel its type, size and shape. Contractor are using bar bending schedule (B.B.S) for ordering the steel bar for proceeding the construction. Steel fixer using bar bending schedule (B.B.S) for doing their work or installing the bar in column, beam or slab according to the B.B.S (B.B.S) that how much cut length or bending of bar will be needed and which size of steel should be use. The inspector and clerks of construction refers to the B.B.S to make are that the reinforcement work in the field is in proper with the design reinforcement as per drawing.

B.B.S for Column.

detail of column

Details from the diagram.

  • Thickness of slab is150 mm
  • Floor height is 3 m or 3000 mm
  • Footing depth is 400 mm
  • Development Length is 50d
  • Column has 8 numbers of 16 mm dia bars
  • Stirrup spacing is 8mm @ 150 mm C/C
  • Concrete Cover of Footing is 40 mm
  • Concrete Cover of slab is 25 mm

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Bar Bending Schedule For Column

Steps for B.B.S of Column.

Generally, there are five steps for preparing the bar bending schedule of column these five is given below:

  • Find the length of Vertical Bar
  • Find out lapping
  • Cutting Length of Stirrups
  • Number of Stirrups
  • B.B.S

Find the length of Vertical Bar.

Length of Vertical bar = Development length (Ld) + footing depth + Floor Heights + Slab Thicknesses + Overlap Length

= (12×16) +400+ (3000) +(150) +(50×16)

= 4734 mm or 4.73 m

Now we find the length of one vertical bar.

The total length of vertical bar = 4732 x number of steels in column

The total length of vertical bar = 4732 x 8

The total length of vertical bar = 37856 mm

Find out lapping.

length of lapping is 50d

Lapping length = 50 x Dia of steel

Length of lapping = 50×20 = 1000 mm.

We know that the length of typical steel is 12.25 m or 40 feet length

Total Length of Vertical Bar = 37.856 m that is more than 12.25 m or 40 feet so lapping should be provided.

Length of lapping is 1000 mm the result will be 37856 + 1 = 38.856 m

It is mentioned already in this article, consider the points while lapping the bar. There is no one right process we can use. Just remember the lines.

  • Don’t tie a column at bottom and also at top
  • Lap at another bars every time
  • Overlap top bars with bottom bars always

Cutting Length of Stirrups.

we already discussed cut length of stirrup in B.B.S of beam article.

Length of One Hook = 9d

Cutting length of Stirrup = (Perimeter of stirrup – concrete cover) + Number of Hooks

Cutting length of stirrup = (πd-cc) + (2 hooks)

Cutting length of stirrup = (3.14×450-25) +(2x9d)

= (1413-25) + (2×9×16)

= 1388 + 288

Cutting length of Stirrup = 1676 mm

Number of Stirrups.

Number of stirrups = (Total length of Column ÷ spacing of stirrups) +1

Number of stirrups = 4773 ÷ 150 + 1

Number of stirrups = 32.82 say 33 numbers

Bar Bending Schedule.

The B.B.S of column is shown below in table

S. NO

Bar Mark

Bar dia

No of bars

Length (m)

unit weight(m/kg)

weight of steel (Kg)

1

Vertical Bar

20

8

4.773

2.4666

94.18

2

Stirrups Bar

8

33

1.676

0.395

21.84

Total Weight of Reinforced Concrete Column

116.02

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Bar Bending Schedule for RCC Slab With Complete Details

 

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