Bar Bending Schedule for Reinforcement Slab
Bar Bending Schedule for RCC Slab With Complete Details
B.B.S for R.C.C Slab.
In This article will will discuss about How to prepare bar bending schedule for RCC Slab
To preparing bar bending schedule for a Slab. there are some criteria and the assumptions that require to be met. Let’s get started..
Forces on RCC Slab
You should know about the normal forces action on a Slab.
If u see the shear force and bending moment diagram, The slab has high moments at the center and less at ends. The shear force is maximum at the ends while at the center shear force is 0 or minimum.
 Use less cutting of the steel and provide desirable lapping.
 Lap another steels at the same time.
 Don’t Overlap at same position and place.
 Between the laps end 2 end spacing should be provided.
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Bar Bending Schedule Of Column
Bar Bending Schedule Is Used by.
Bar bending schedule is used by different kind of the peoples and officials on the construction site which is given below.
 Quantity Surveyor
 Steel fixer
 Contractor
 Project Manager
 Inspectors
 Clerks of Construction
In the Construction Site all Estimation and Costing Operation is Responsibilities of ( QS ) Quantity Surveyor. The bar bending schedule gives the details to ( QS ) Quantity Surveyor for finding out the number of steel its type, size and shape. Contractor are using bar bending schedule for ordering the steel bar for proceeding the construction. Steel fixer using bar bending schedule for doing their work or installing the bar in column, beam or slab according to the bar bending schedule that how much cut length or bending of bar will be needed and which size of steel should be use. The inspector and clerks of the construction refers to the B.B.S to make are that the reinforcement work in the field is in proper with the design of reinforcement as per drawing.
Bar Bending Schedule for RCC Slab.
Details Of Diagram
 Thickness of the slab is150 mm
 Development Length is 50d
 Bottom bar of the slab will be provided 12 mm dia of the steel is at 200 mm center 2 center spacing.
 Top bar of the slab will be provided 12 mm dia of the steel is at 200 mm center 2 center spacing.
 Extra bar of the slab at x axis will be provided 12 mm dia of the steel is at 125 mm center 2 center spacing.
 Extra bar of the slab at y axis will be provided 12 mm dia of the steel is at 125 mm center 2 center spacing.
 Stirrup Spacing is 8mm @ 150 mm C to C.
 Concrete Cover of the Slab is 25 mm.
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Bar Bending Schedule For Footing
Steps for (B.B.S) of the Slab.
Generally, There are the five steps for preparing the bar bending schedule of the column these five is given below.
 Number of the steel.
 Cut length of the steel.
 Find out the lapping.
 Bar Bending Schedule.
Number of The Steels,
Numbers of the steel in Main bar.
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 200 + 1
Number of stirrups = 26 numbers
Numbers of the steel in Distribution bar.
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 200 + 1
Number of stirrups = 26 numbers
Numbers of the Extra bar at xaxis
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 125 + 1
Number of stirrups = 41 numbers
Numbers of the Extra bar at yaxis.
Number of steels = (Total length of slab ÷ spacing of bar) +1
Number of stirrups = 5000 ÷ 125 + 1
Number of stirrups = 41 numbers
Cut length of the steel.
Cut Length of the Main Bar.
Length of Main bar = slab length – 2(concrete cover) + Development length (Ld) + Overlap Length
= 5000 – 2(25) + (12×12) + (50×12)
= 5694 mm or 5.69 m
Now We Can find the length of bar.
The total length of Main bar = 5694 x number of steels in slab
The total length of bar = 5694 x 26
The total length of bar = 148044 mm or 148 meter
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Bar bending schedule Of Circular Column
Cut Length of the Distribution Bar.
Length of Distribution bar = slab length – 2(concrete cover) + Development length (Ld) + Overlap Length
= 5000 – 2(25) + (12×12) + (50×12)
= 5694 mm or 5.69 m
Now we find the length of bar.
The total length of Distribution bar = 5694 x number of steels in slab
The total length of Distribution bar = 5694 x 26
The total length of bar = 148044 mm or 148 meter
Cut Length of Extra Bar at xaxis.
Total Length of extra bar = Length of extra bar – concrete cover
= 1500 – 2(25)
= 1450 mm or 1.450 meter
Now we find the length of bar.
The total length of extra bar at x axis = 1450 x number of extra bar in slab
The total length of bar = 1450 x 41
The total length of bar = 59450 mm or 59.45 meter
Cut Length of Extra Bar at yaxis.
Length of Extra Bar at yaxis = slab length – 2(concrete cover)
= 1500 – 2(25)
= 1450 mm or 1.40 m
Now We Find the length Of The bar.
The total length of the Extra bar = 1450 x number of extra bar in slab
The total length of the bar = 1450 x 41
The total length of the bar = 59450 mm or 59.45 meter
Find out lapping.
Main Bar.
length of lapping is 50d
Lapping length = 50 x Dia of steel
Length of lapping = 50×12 = 600 mm.
We know that the length of the typical steel is 12.25 m or 40 feet length
Total Length of the Main Bar = 148044 m that is more than 12.25 m or 40 feet so lapping should be provided.
Length of the lapping is 600 mm the result will be 148044 + 600 = 148644 m
It is mentioned already in this article, Consider the points while lapping the bar. There is no one right process we can use. Just remember the lines.
 Don’t tie a column at the bottom & also at the top
 Lap at the another bars every time
 Overlap top bars with the bottom bars always
Distribution Bar.
length of lapping is 50d
Lapping length = 50 x Dia of steel
Length of lapping = 50×12 = 600 mm.
We know that the length of typical steel is 12.25 m or 40 feet length
Total Length of the Main Bar = 148044 m that is more than 12.25 m or 40 feet so lapping should be provided.
Length of the lapping is 600 mm the result will be 148044 + 600 = 148644 m
It is the mentioned already in this article, consider the points while lapping the bar. There is no one right process we can use. Just remember the lines.
 Don’t tie a column at the bottom and also at the top.
 Lap at another bars every times.
 Overlap top bars with the bottom bars always.
Learn More
Calculate Bar Bending Schedule For Lintel Beam
Number of The Steels
Numbers of The steel in Main bar
Number of the steels = (Total length of slab ÷ spacing of bar) +1
Number of the stirrups = 5000 ÷ 200 + 1
Number of the stirrups = 26 numbers
Numbers of the steel in Distribution bar:
Number of the steels = (Total length of slab ÷ spacing of bar) +1
Number of the stirrups = 5000 ÷ 200 + 1
Number of the stirrups = 26 numbers
Numbers of The Extra bar at xaxis.
Number of the steels = (Total length of slab ÷ spacing of bar) +1
Number of the stirrups = 5000 ÷ 125 + 1
Number of the stirrups = 41 numbers
Numbers of The Extra bar at yaxis.
Number of the steels = (Total length of the slab ÷ Spacing of bar) +1
Number of the stirrups = 5000 ÷ 125 + 1
Number of the stirrups = 41 numbers
Bar Bending Schedule ( BBS ).
The Bar bending schedule of the column is shown below in table
S. NO 
Bar Mark 
Bar dia 
No of bars 
Length (m) 
unit weight(m/kg) 
weight of steel (Kg) 
1 
Main Bar 
12 
26 
148 
0.888 
3417 
2 
Distribution Bar 
12 
26 
148 
0.888 
3417 
3 
Extra Bar xaxis 
12 
41 
59.45 
0.888 
2164.45 
4 
Extra Bar yaxis 
12 
41 
59.45 
0.888 
2164.45 
Total Weight of Reinforced Concrete Slab 
11163 
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