Bar Bending Schedle

Bar Bending Schedule and Staircase Reinforcement Details

How to Calculate Staircase Concrete & Bar Bending Schedule & Staircase Reinforcement Details.

 

Bar Bending Schedule And Staircase Reinforcement

Stair rise and run calculator

Calculation of Staircase 3 Different Parts as Below

1. Concrete Calculation for the Staircase
2. Bar Bending Schedule for the Staircase

First, start calculation of staircase sum basic knowledge of the staircase

Most Important Point In This Article

stair case

A various part of the Stair

Step

• A flat surface, especially one in the series, on which to place one’s foot when moving from the one level to another. all step is composed of the tread and riser.

Tread

• Tread is a scrap of stairway that’s stepped in. It’s the top or flat surface to press beneath the feet.

• It’s trodden on while climbing or descending staircase.

• It’s constructed to same thickness as another floor. There’s always one fewer tread than risers at the stairs.

• The general horizontal distance of the stairs is going to be number of threads added together.

• The horizontal projection of a step in the staircase is called tread. It is also known as going

• In residential buildings, the tread length provided is 250 mm while in the public buildings maximum length is 270 mm to 300 mm.

Learn More

  1. How To Calculate The Cutting Length Of the Stirrups In Beam And Column

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Riser

• This riser is vertical portion between each tread on stair.

• Not all stairs have risers. The rise-less steps are called open thread.

• Open riser stairs have grown in the popularity Recently years. Closed tread stair has risers included.

• This vertical board forms the face of the step, also forms the space between one step and the next.

• Rise provided could be a uniform. It is normally hight 150 mm to 175 mm in the residential buildings while it is kept between hight 120 mm to 150 mm in the public buildings.

• However, in the commercial buildings, more rise is provided from the consideration of economic floor area.

Nosing

• Nosing is flat protruding edge of a stair at which most foot traffic occurs.

• Mostly, it’s half curved molding fixed into the ends of those threads exposed at a half that covers where the balusters fit into the treads.

• Nosing is the border of tread projecting beyond the face of riser and face of the cut string. This is the place where the thread above a riser overhangs it. Sometimes, tread may not have a nosing.

Base Rail or Shoe Rail

• For systems in which the baluster doesn’t start at the treads, they go to a base rail. This allows for the identical balusters, avoiding this second baluster problem.

Landing

• This is a platform provided btw two flights.

1. Concrete Calculation for the Staircase

detail 1

detail 2

Concrete calculation

Section 1

Landing area concrete = L x B x H

Landing area concrete = 1.7 M.  x 3.25 M. x 0.150 M.

Landing area concrete = 0.830 Cu.m.——–(1)

Section 2

Waist slab area concrete = L x B x H x N

Waist slab area concrete = 3.85 M. x 1.5 m. x 0.150 M. x 2 Nos.

Waist slab area concrete = 1.732 Cu.m. ——–(2)

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Section 3

Steps area concrete = L x Volium of trianglar area x N x Q

Steps area concrete = 1.5 M. x( 0.300 M. x 0.150 M x (1/2)) x 2 Nos. X 11 Qty

Steps area concrete = 0. 75 Cu.m. ——–(3)

Section 4

Beam area concrete = L x B x H X N

Beam area concrete = 1.5 M. x 0.44 M. x 0.300 M. x 2 Nos.

Landing area concrete =0.400 Cu.m.——–(4)

Total Concrete of the Staircase = (1) + (2) + (3) + (4)

Total Concrete of the Staircase = 0.830 Cu.m. + 1.732 Cu.m. + 0. 75 Cu.m. + 0.400 Cu.m.

Total Concrete of the Staircase = 3.712 Cu.m.

2. Bar Bending Schedule for the Staircase

Reinforcement

Section 1

Landing Area Bar Bending Schedule

Distribution bar 8 mm C/C 120 mm Length 3.25 in Y-axis Distribution area 1.5m

So No, of 8 mm Steel bar = 1.5 M. / 0.120 M. = 12.5 Nos

Consider 13 Nos. steel bar use Top Side +13 Nos Steel use Bottom Side

Weight of distribution of 8 mm dia steel bar = L x Nos of steel x Weight of Steel 

Weight of distribution of 8 mm dia steel bar = 3.25 x 13 x 2 x 0.395               (0.395 kg/m is 8mm dia steel bar weight)

Weight of distribution of 8 mm dia steel bar = 33.34 kg ——– (1)

Section 1 Total = 33.34 kg

Learn More

Bar Bending Schedule of the beam

Section 2-1

Waist slab Bar Bending Schedule

Distribution bar 8 mm C/C 140 mm Length 1.5 in Y-axis Distribution area 3.89m

So No, of 8 mm Steel bar = 3.89 M. / 0.140 M. = 27.75 Nos

Consider 28 Nos. steel bar use Top Side +28 Nos Steel use Bottom Side

Weight of distribution of 8 mm dia steel bar = L x Nos of steel x Weight of Steel 

Weight of distribution of 8 mm dia steel bar = 1.5 x 28 x 2 x 0.395               (0.395 kg/m is 8mm dia steel bar weight)

Weight of distribution of 8 mm dia steel bar = 33.1 kg ——– (2-1-1)

Main bar Bottom Area 10mm dia C/c 80 mm distance 

Length of main bar bottom area = 1.5 M. – 0.180 M.  + 0.150 M. + 3.89 M. + 0.450 M.

Length of main bar bottom area = 5.81 m

Nos of bar 10 mm dia C/c 80 mm distance = 1.5 M. / 0.080 M. = 18.75  Nos.

Consider 19 Nos. steel bar use Bottom bar Side

Main bar Bottom Area 10mm dia steel bar = 5.81 M. X 19 Nos. X 0.617 kg/m               (0.617 kg/m is 10mm dia steel bar weight)

Main bar Bottom Area 10mm dia steel bar = 68.11 kg ——– (2-1-2)

Learn More

Estimate this Slab (Drawing Included).

Civil Engineering Interviews Questions And Answers

Main bar Top Area 10mm dia C/c 80 mm distance 

Length of main bar top area = 1.7 M. – 0.180 M.  + 3.89 M. + 0.450 M. +0.250 M.

Length of the main bar top area = 6.11 m

Nos of bar 10 mm dia C/c 80 mm distance = 1.5 M. / 0.080 M. = 18.75  Nos.

Consider 19 Nos. steel bar use Bottom bar Side

Main bar Top Area 10-mm dia steel bar = 6.11 M. X 19 Nos. X 0.617 kg/m               (0.617 kg/m is 10mm dia steel bar weight)

Main bar Bottom Area 10mm dia steel bar = 71.63 kg ——– (2-1-3)

Section 2-1  total = 33.1 kg + 68.11 kg + 71.63 kg = 172.84 kg 

Section 2-2

Waist slab Bar Bending Schedule

Distribution bar 8 mm C/C 140 mm Length 1.5 in Y-axis Distribution area 3.83m

So No, of 8 mm Steel bar = 3.83 M. / 0.140 M. = 27.75 Nos

Consider 28 Nos. steel bar use Top Side +28 Nos Steel use Bottom Side

Weight of distribution of 8 mm dia steel bar = L x Nos of steel x Weight of Steel 

Weight of distribution of 8 mm dia steel bar = 1.5 x 28 x 2 x 0.395  (0.395 kg/m is 8mm dia steel bar weight)

Weight of distribution of 8 mm dia steel bar = 33.1 kg ——– (2-2-1)

Main bar Bottom Area 10mm dia C/c 80 mm distance 

Length of the main bar bottom area = 1.5 M. – 0.180 M.  + 0.150 M. + 3.83 M. + 0.450 M.

Length of main bar bottom area = 5.78 m

Nos of bar 10 mm dia C/c 80 mm distance = 1.5 M. / 0.080 M. = 18.75  Nos.

Consider 19 Nos. steel bar use Bottom bar Side

Main bar Bottom Area 10mm dia steel bar = 5.78 M. X 19 Nos. X 0.617 kg/m               (0.617 kg/m is 10mm dia steel bar weight)

Main bar Bottom Area 10mm dia steel bar = 67.75 kg ——– (2-2-2)

Main bar Top Area 10mm dia C/c 80 mm distance 

Length of main bar top area = 1.7 M. – 0.180 M.  + 3.83 M. + 0.450 M. +0.250 M.

Length of the  main bar top area = 6.05m

Nos of bar 10 mm dia C/c 80 mm distance = 1.5 M. / 0.080 M. = 18.75  Nos.

Consider 19 Nos. steel bar use Bottom bar Side

Main bar Top Area 10mm dia steel bar = 6.05 M. X 19 Nos. X 0.617 kg/m               (0.617 kg/m is 10mm dia steel bar weight)

Main bar Bottom Area 10mm dia steel bar = 70.92 kg ——– (2-2-3)

Section 2-2 Total =  31.1 kg + 68.09 kg +70.92 kg = 170.11 kg

Total Section 2 weight = 172.84 kg + 170.11 kg = 342.95 kg

Section 3

Beam area bar bending schedule

8mm dia Ring Size for length of the column ring = Column Size – Cover

Ring Size for length of column ring  = ( L of Column – cover – cover + B of Column – cover – cover + Hook ) x 2

Ring Size for length of column ring = (600 -25 -25 + 300 – 25 -25 +8 ) x 2

8mm dia  Ring Size for lenth of column ring = 1.616 M.

Reinforcement 1

No ring requirement = Length / Spacing

No ring requirement = 1.5 /0.140 = 11 Nos

Weight of ring  = 1.616 x 11 x 0.395 = 7.02 kg ——–(3-1)

Length of Bar = Length of the bar +( wall bering + wall bering ) + ( End side L Bend x No of Qty )

12 mm dia Length of Bar = 1.5 + (0.200 + 0. 200 )  + (0. 300 X 4)

Length of Bar = 3.1 M.

Weight of ring Main bar  = 3.1 x 6 x 0.89 = 16.554 kg ——–(3-2)               (0.89 kg/m is 12mm dia steel bar weight)

Section 3 total = 7.02 kg + 16.554 kg = 23.57 kg x 2 ( Because of same two beam ) = 47.51 kg

Total Weight of Staircase Bar Bending schedule

Section 1 + Section 2 + Section 3 

= 33.34 kg + 342.95 kg + 47.51 kg

Total Weight of  Staircase Bar Bending schedule  = 423.79 kg.


Other Post

  1. How to Calculate the Unit Weight of the Steel Bars | Bar Bending Schedule

  2. Calculation Method For Find Out The Overlapping Length Of Beam, Column And Slab

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  4. CIVIL ENGINEERING COMPETITIVE QUESTIONS


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